3.21.83 \(\int \frac {x}{\sqrt {2+5 x-3 x^2}} \, dx\)

Optimal. Leaf size=38 \[ -\frac {1}{3} \sqrt {-3 x^2+5 x+2}-\frac {5 \sin ^{-1}\left (\frac {1}{7} (5-6 x)\right )}{6 \sqrt {3}} \]

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Rubi [A]  time = 0.01, antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.188, Rules used = {640, 619, 216} \begin {gather*} -\frac {1}{3} \sqrt {-3 x^2+5 x+2}-\frac {5 \sin ^{-1}\left (\frac {1}{7} (5-6 x)\right )}{6 \sqrt {3}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[x/Sqrt[2 + 5*x - 3*x^2],x]

[Out]

-Sqrt[2 + 5*x - 3*x^2]/3 - (5*ArcSin[(5 - 6*x)/7])/(6*Sqrt[3])

Rule 216

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[(Rt[-b, 2]*x)/Sqrt[a]]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rule 619

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Dist[1/(2*c*((-4*c)/(b^2 - 4*a*c))^p), Subst[Int[Si
mp[1 - x^2/(b^2 - 4*a*c), x]^p, x], x, b + 2*c*x], x] /; FreeQ[{a, b, c, p}, x] && GtQ[4*a - b^2/c, 0]

Rule 640

Int[((d_.) + (e_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(e*(a + b*x + c*x^2)^(p +
1))/(2*c*(p + 1)), x] + Dist[(2*c*d - b*e)/(2*c), Int[(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, p}
, x] && NeQ[2*c*d - b*e, 0] && NeQ[p, -1]

Rubi steps

\begin {align*} \int \frac {x}{\sqrt {2+5 x-3 x^2}} \, dx &=-\frac {1}{3} \sqrt {2+5 x-3 x^2}+\frac {5}{6} \int \frac {1}{\sqrt {2+5 x-3 x^2}} \, dx\\ &=-\frac {1}{3} \sqrt {2+5 x-3 x^2}-\frac {5 \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-\frac {x^2}{49}}} \, dx,x,5-6 x\right )}{42 \sqrt {3}}\\ &=-\frac {1}{3} \sqrt {2+5 x-3 x^2}-\frac {5 \sin ^{-1}\left (\frac {1}{7} (5-6 x)\right )}{6 \sqrt {3}}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 38, normalized size = 1.00 \begin {gather*} -\frac {1}{3} \sqrt {-3 x^2+5 x+2}-\frac {5 \sin ^{-1}\left (\frac {1}{7} (5-6 x)\right )}{6 \sqrt {3}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[x/Sqrt[2 + 5*x - 3*x^2],x]

[Out]

-1/3*Sqrt[2 + 5*x - 3*x^2] - (5*ArcSin[(5 - 6*x)/7])/(6*Sqrt[3])

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IntegrateAlgebraic [A]  time = 0.13, size = 56, normalized size = 1.47 \begin {gather*} -\frac {1}{3} \sqrt {-3 x^2+5 x+2}-\frac {5 \tan ^{-1}\left (\frac {\sqrt {3} \sqrt {-3 x^2+5 x+2}}{3 x+1}\right )}{3 \sqrt {3}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[x/Sqrt[2 + 5*x - 3*x^2],x]

[Out]

-1/3*Sqrt[2 + 5*x - 3*x^2] - (5*ArcTan[(Sqrt[3]*Sqrt[2 + 5*x - 3*x^2])/(1 + 3*x)])/(3*Sqrt[3])

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fricas [B]  time = 0.41, size = 55, normalized size = 1.45 \begin {gather*} -\frac {5}{18} \, \sqrt {3} \arctan \left (\frac {\sqrt {3} \sqrt {-3 \, x^{2} + 5 \, x + 2} {\left (6 \, x - 5\right )}}{6 \, {\left (3 \, x^{2} - 5 \, x - 2\right )}}\right ) - \frac {1}{3} \, \sqrt {-3 \, x^{2} + 5 \, x + 2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(-3*x^2+5*x+2)^(1/2),x, algorithm="fricas")

[Out]

-5/18*sqrt(3)*arctan(1/6*sqrt(3)*sqrt(-3*x^2 + 5*x + 2)*(6*x - 5)/(3*x^2 - 5*x - 2)) - 1/3*sqrt(-3*x^2 + 5*x +
2)

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giac [A]  time = 0.21, size = 26, normalized size = 0.68 \begin {gather*} \frac {5}{18} \, \sqrt {3} \arcsin \left (\frac {6}{7} \, x - \frac {5}{7}\right ) - \frac {1}{3} \, \sqrt {-3 \, x^{2} + 5 \, x + 2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(-3*x^2+5*x+2)^(1/2),x, algorithm="giac")

[Out]

5/18*sqrt(3)*arcsin(6/7*x - 5/7) - 1/3*sqrt(-3*x^2 + 5*x + 2)

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maple [A]  time = 0.05, size = 27, normalized size = 0.71 \begin {gather*} \frac {5 \sqrt {3}\, \arcsin \left (\frac {6 x}{7}-\frac {5}{7}\right )}{18}-\frac {\sqrt {-3 x^{2}+5 x +2}}{3} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/(-3*x^2+5*x+2)^(1/2),x)

[Out]

5/18*3^(1/2)*arcsin(6/7*x-5/7)-1/3*(-3*x^2+5*x+2)^(1/2)

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maxima [A]  time = 1.98, size = 26, normalized size = 0.68 \begin {gather*} -\frac {5}{18} \, \sqrt {3} \arcsin \left (-\frac {6}{7} \, x + \frac {5}{7}\right ) - \frac {1}{3} \, \sqrt {-3 \, x^{2} + 5 \, x + 2} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(-3*x^2+5*x+2)^(1/2),x, algorithm="maxima")

[Out]

-5/18*sqrt(3)*arcsin(-6/7*x + 5/7) - 1/3*sqrt(-3*x^2 + 5*x + 2)

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mupad [B]  time = 1.14, size = 46, normalized size = 1.21 \begin {gather*} -\frac {\sqrt {-3\,x^2+5\,x+2}}{3}-\frac {\sqrt {3}\,\ln \left (\sqrt {-3\,x^2+5\,x+2}+\frac {\sqrt {3}\,\left (3\,x-\frac {5}{2}\right )\,1{}\mathrm {i}}{3}\right )\,5{}\mathrm {i}}{18} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x/(5*x - 3*x^2 + 2)^(1/2),x)

[Out]

- (3^(1/2)*log((5*x - 3*x^2 + 2)^(1/2) + (3^(1/2)*(3*x - 5/2)*1i)/3)*5i)/18 - (5*x - 3*x^2 + 2)^(1/2)/3

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {x}{\sqrt {- \left (x - 2\right ) \left (3 x + 1\right )}}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x/(-3*x**2+5*x+2)**(1/2),x)

[Out]

Integral(x/sqrt(-(x - 2)*(3*x + 1)), x)

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